https://gcc.gnu.org/bugzilla/show_bug.cgi?id=81122
--- Comment #10 from Ben Woodard <woodard at redhat dot com> --- Also note: https://connect.microsoft.com/VisualStudio/feedback/details/742775 My reading of: https://wg21.link/lwg2381 is that if the first part of the number includes a '.' then the portion after the 'p' or 'P' is not part of the number and is left in the string. The example is 0x1a.bp+07p So I believe that your assertion that 2381 applies in this situation is not accurate. This example refers to the number: 26.6875 (16+10+11/16) and because there is already a hexadecimal point '.' separating the integral portion from the fractional portion the 'p' is not part of the number. However, if the number was: "0x1abp+07p" (note the absence of the '.') then the number would be: in the normal hexfloat format and refer to 1752839.0 leaving the trailing 'p' in the stream.
