[Bug c++/86082] user-defined literals are not converted to the execution charset

[krebbel at gcc dot gnu.org]

https://gcc.gnu.org/bugzilla/show_bug.cgi?id=86082

--- Comment #3 from Andreas Krebbel <krebbel at gcc dot gnu.org> ---
Author: krebbel
Date: Mon Jun 25 07:16:59 2018
New Revision: 262003

URL: https://gcc.gnu.org/viewcvs?rev=262003&root=gcc&view=rev
Log:
C++: Fix PR86082

When turning a user-defined numerical literal into an operator
invocation the literal needs to be translated to the execution
character set.

gcc/cp/ChangeLog:

2018-06-25  Andreas Krebbel  <kreb...@linux.ibm.com>

        PR C++/86082
        * parser.c (make_char_string_pack): Pass this literal chars
        through cpp_interpret_string.
        (cp_parser_userdef_numeric_literal): Check the result of
        make_char_string_pack.

gcc/testsuite/ChangeLog:

2018-06-25  Andreas Krebbel  <kreb...@linux.ibm.com>

        PR C++/86082
        * g++.dg/pr86082.C: New test.


Added:
    trunk/gcc/testsuite/g++.dg/pr86082.C
Modified:
    trunk/gcc/ChangeLog
    trunk/gcc/cp/parser.c
    trunk/gcc/testsuite/ChangeLog