https://gcc.gnu.org/bugzilla/show_bug.cgi?id=113958
--- Comment #1 from Andrew Pinski <pinskia at gcc dot gnu.org> ---
You can use visibility on the type even Like:
```
struct __attribute__ ((visibility("default"))) Foo1{
virtual void some_member() = 0;
};
struct __attribute__ ((visibility("default"))) Foo : Foo1 {
virtual void some_member();
};
```
Which changes the visibility back to default for the whole class.
This is documented here:
https://gcc.gnu.org/onlinedocs/gcc-13.2.0/gcc/Common-Type-Attributes.html#index-visibility-type-attribute
You can also use the `pragma GCC visibility` too in the same way:
https://gcc.gnu.org/onlinedocs/gcc-13.2.0/gcc/Visibility-Pragmas.html#index-pragma_002c-visibility
#pragma GCC visibility push(default)
Though visibility on the struct applies to all methods too. Which I suspect you
want really instead of marking each method as being default.
The pragma push/pop makes it easier to mark the classes you want to be exported
too. E.g. you can wrap including a header file with that to make sure those are
exported.
