[Bug c++/107953] Greater-than operator misparsed inside a lambda expression used as a template argument

[cvs-commit at gcc dot gnu.org via Gcc-bugs]

https://gcc.gnu.org/bugzilla/show_bug.cgi?id=107953

--- Comment #6 from GCC Commits <cvs-commit at gcc dot gnu.org> ---
The trunk branch has been updated by Jason Merrill <ja...@gcc.gnu.org>:

https://gcc.gnu.org/g:00e8690ef0d7ac1ced87ceee309dbfa27909a35c

commit r16-3444-g00e8690ef0d7ac1ced87ceee309dbfa27909a35c
Author: Jason Merrill <ja...@redhat.com>
Date:   Sun Aug 24 05:15:01 2025 -0400

    c++: > in lambda in template arg [PR107953]

    As with PR116928, we need to set greater_than_is_operator_p within the
    lambda delimiters.

            PR c++/107953

    gcc/cp/ChangeLog:

            * parser.cc (cp_parser_lambda_expression): Set
            greater_than_is_operator_p.

    gcc/testsuite/ChangeLog:

            * g++.dg/cpp2a/lambda-targ18.C: New test.