https://gcc.gnu.org/bugzilla/show_bug.cgi?id=119402
--- Comment #7 from Andrew Pinski <pinskia at gcc dot gnu.org> --- _2 = zero_one * b; _4 = _2 & _3; I think I am going with: ``` (for bop (bit_and bit_xor bit_ior) (simplify (bop:c (mult:cs zero_one_value@0 @1) @2) (mult @0 (bop @1 @2)) ``` Because it applies for all bitops and not just and. This is for next week.
