https://gcc.gnu.org/bugzilla/show_bug.cgi?id=119402

--- Comment #7 from Andrew Pinski <pinskia at gcc dot gnu.org> ---
  _2 = zero_one * b;
  _4 = _2 & _3;

I think I am going with:
```
(for bop (bit_and bit_xor bit_ior)
 (simplify
  (bop:c (mult:cs zero_one_value@0 @1) @2)
  (mult @0 (bop @1 @2))
```

Because it applies for all bitops and not just and. This is for next week.

Reply via email to