On 10/24/2011 02:47 PM, Gabriel Dos Reis wrote:
What about (testcase)

      int f(char);
      double f(...);

      const int n = sizeof f({257});

?

The narrowing conversion would be marked as 'bad' and therefore the second overload chosen. As before, the objective is to only change the diagnostic, not the meaning of valid code.

Jason

Reply via email to