On Tue, Nov 08, 2022 at 03:06:53PM +0100, Aldy Hernandez wrote: > +// If either operand is a NAN, set R to the combination of both NANs > +// signwise and return TRUE.
This comment doesn't describe what it does now.
If either operand is a NAN, set R to NAN with unspecified sign bit and return
TRUE.
?
Other than this LGTM.
Jakub
