Am Montag, dem 06.05.2024 um 11:07 +0200 schrieb Richard Biener: > On Mon, 6 May 2024, Martin Uecker wrote: > > > Am Montag, dem 06.05.2024 um 09:00 +0200 schrieb Richard Biener: > > > On Sat, 4 May 2024, Martin Uecker wrote: > > > > > > > Am Freitag, dem 03.05.2024 um 21:16 +0200 schrieb Jakub Jelinek: > > > > > > On Fri, May 03, 2024 at 09:11:20PM +0200, Martin Uecker wrote: > > > > > > > > > > TYPE_CANONICAL as used by the middle-end cannot express > > > > > > > > > > this but > > > > > > > > > > > > > > > > Hm. so how does it work now for arrays? > > > > > > > > > > > > Do you have a testcase which doesn't work correctly with the arrays? > > > > > > > > I am mostly trying to understand better how this works. But > > > > if I am not mistaken, the following example would indeed > > > > indicate that we do incorrect aliasing decisions for types > > > > derived from arrays: > > > > > > > > https://godbolt.org/z/rTsE3PhKc > > > > > > This example is about pointer-to-array types, int (*)[2] and > > > int (*)[1] are supposed to be compatible as in receive the same alias > > > set. > > > > In C, char (*)[2] and char (*)[1] are not compatible. But with > > COMPAT set, the example operates^1 with char (*)[] and char (*)[1] > > which are compatible. If we form equivalence classes, then > > all three types would need to be treated as equivalent. > > > > ^1 Actually, pointer to functions returning pointers > > to arrays. Probably this example can still be simplified... > > > > > This is ensured by get_alias_set POINTER_TYPE_P handling, > > > the alias set is supposed to be the same as that of int *. It seems > > > we do restrict the handling a bit, the code does > > > > > > /* Unnest all pointers and references. > > > We also want to make pointer to array/vector equivalent to > > > pointer to > > > its element (see the reasoning above). Skip all those types, > > > too. > > > */ > > > for (p = t; POINTER_TYPE_P (p) > > > || (TREE_CODE (p) == ARRAY_TYPE > > > && (!TYPE_NONALIASED_COMPONENT (p) > > > || !COMPLETE_TYPE_P (p) > > > || TYPE_STRUCTURAL_EQUALITY_P (p))) > > > || TREE_CODE (p) == VECTOR_TYPE; > > > p = TREE_TYPE (p)) > > > > > > where the comment doesn't exactly match the code - but C should > > > never have TYPE_NONALIASED_COMPONENT (p). > > > > > > But maybe I misread the example or it goes wrong elsewhere. > > > > If I am not confusing myself too much, the example shows that > > aliasing analysis treats the the types as incompatible in > > both cases, because it does not reload *a with -O2. > > > > For char (*)[1] and char (*)[2] this would be correct (but an > > implementation exploiting this would need to do structural > > comparisons and not equivalence classes) but for > > char (*)[2] and char (*)[] it is not. > > Oh, these are function pointers, so it's about the alias set of > a pointer to FUNCTION_TYPE. I don't see any particular code > trying to make char[] * (*)() and char[1] *(*)() inter-operate > for TBAA iff the FUNCTION_TYPEs themselves are not having the > same TYPE_CANONICAL. > > Can you open a bugreport and please point to the relevant parts > of the C standard that tells how pointer-to FUNCTION_TYPE TBAA > is supposed to work?
https://gcc.gnu.org/bugzilla/show_bug.cgi?id=114959 Martin > > Thanks, > Richard. > > > Martin > > > > > > > > > > Richard. > > > > > > > Martin > > > > > > > > > > > > > > > > E.g. same_type_for_tbaa has > > > > > > type1 = TYPE_MAIN_VARIANT (type1); > > > > > > type2 = TYPE_MAIN_VARIANT (type2); > > > > > > > > > > > > /* Handle the most common case first. */ > > > > > > if (type1 == type2) > > > > > > return 1; > > > > > > > > > > > > /* If we would have to do structural comparison bail out. */ > > > > > > if (TYPE_STRUCTURAL_EQUALITY_P (type1) > > > > > > || TYPE_STRUCTURAL_EQUALITY_P (type2)) > > > > > > return -1; > > > > > > > > > > > > /* Compare the canonical types. */ > > > > > > if (TYPE_CANONICAL (type1) == TYPE_CANONICAL (type2)) > > > > > > return 1; > > > > > > > > > > > > /* ??? Array types are not properly unified in all cases as we > > > > > > have > > > > > > spurious changes in the index types for example. Removing this > > > > > > causes all sorts of problems with the Fortran frontend. */ > > > > > > if (TREE_CODE (type1) == ARRAY_TYPE > > > > > > && TREE_CODE (type2) == ARRAY_TYPE) > > > > > > return -1; > > > > > > ... > > > > > > and later compares alias sets and the like. > > > > > > So, even if int[] and int[0] have different TYPE_CANONICAL, they > > > > > > will be considered maybe the same. Also, guess get_alias_set > > > > > > has some ARRAY_TYPE handling... > > > > > > > > > > > > Anyway, I think we should just go with Richi's patch. > > > > > > > > > > > > Jakub > > > > > > > > > > > > > > > > > > > > > > > > > >
