On Sun, 10 Feb 2013, Manuel López-Ibáñez wrote: >> The only question I have is about "unless the variable is a function". >> How can a variable be a function? > True. What about: "if a declaration shadows a function decqlaration, > unless the former declares a function or a pointer to function."
Yes, that'll work I think. > I also realized that Wshadow is not C-only, so I will move the item > to C family. Thanks! Gerald
