On Tue, Jul 12, 2005 at 06:25:45PM +0200, Mirco Lorenzoni wrote:
> Can a pointer appear in a C/C++ relational expression which doesn't test the
> equality (or the inequality) of that pointer with respect to another pointer?
> For example, are the comparisons in the following program legal code?
>
> /* test.c */
> #include <stdio.h>
>
> int main(int argc, char* argv[])
> {
> void *a, *b;
> int aa, bb;
>
> a = &aa;
> b = &bb;
>
> printf("a: %p, b: %p\n", a, b);
> if (a < b)
> printf("a < b\n");
> else
> printf("a >= b\n");
>
> if (b < a)
> printf("b < a\n");
> else
> printf("b >= a\n");
> return 0;
> }
No, this is not legal. Relational tests between pointers is only allowed by
the ISO C standard if the two pointers point into the same array, or if a
pointer points to exactly one byte beyond the array.
>
> P.S.
> I'm not a list subscriber. Send me a copy of your reply, please.
Ummm, I don't understand how you expect to get replies if you don't monitor the
list.
--
Michael Meissner
email: [EMAIL PROTECTED]
http://www.the-meissners.org
