On 2007-01-16 15:50:09 +0000, Andrew Haley wrote: > This is a disgreement about interpretation of the langauge in the > standard, which is: > > "The result of the / operator is the quotient from the division of the > first operand by the second; the result of the % operator is the > remainder. In both operations, if the value of the second operand is > zero, the behavior is undefined. When integers are divided, the result > of the / operator is the algebraic quotient with any fractional part > discarded.87) If the quotient a/b is representable, the expression > (a/b)*b + a%b shall equal a." > > If the quotient a/b is *not* representable, is the behaviour of % > well-defined or not? It doesn't say.
The C standard already says "the result of the % operator is the remainder". Then, "If the quotient a/b is representable, the expression (a/b)*b + a%b shall equal a." is just redundant information. -- Vincent Lefèvre <[EMAIL PROTECTED]> - Web: <http://www.vinc17.org/> 100% accessible validated (X)HTML - Blog: <http://www.vinc17.org/blog/> Work: CR INRIA - computer arithmetic / Arenaire project (LIP, ENS-Lyon)
