Question on movmemm: Given
extern int *i, *j; void foo (void) { memcpy (i, j, 10); } I would expect to see argument 4 (the shared alignment) to be sizeof(int) since both argument are pointers to int. What I get instead is 1. Why is that? If I have extern int i[10], j[10]; then I do get larger alignment as expected. paul