print ((struct node *) &SS[0])->name
On 9/3/07, ddd sh <[EMAIL PROTECTED]> wrote:
> hi,
>
> i hav array of following struct which contains 50 elements. I want to
> print only first feild of the struct ie name field in GDB debuggure.
>
>
> struct node {
>
> char name[17] ;
> int age;
> char sex;
> int location
> } SS[50]
>
>
> after running 50 loops if i m using (gdb) print SS
> command it will show the all element and field of the array SS[50]
> but how to get first ie name field of array SS[50]
--
Sincerely,
Vamsi Kundeti
