On Friday 12 February 2010 18:45:01, Michael Snyder wrote: > Paragi, Ajeykumar B wrote: > > Hi, > > > > I have invoked gdb with '-e' command line option on an executable, > > The gdb manual says '-e' is used to set the executable to run. > > But I could not see the symbols read in by gdb when I use -e and could > > not insert breakpoints. > > > > What is the intent of having the command line option "-e" or "-exec"? > > Hmmm, it does seem to be broken.
It's not. `-e' is equivalent to "(gdb) exec-file". It doesn't read its argument for symbols, only for executable to run, or for pure memory contents. > > You can get the same effect, though, by just leaving out the -e flag. > > % gdb my-executable That's equivalent to "(gdb) file", which is equivalent to "gdb -e my-executable -s my-executable", or just "gdb -se my-executable". -- Pedro Alves