Hi. is it possible to replace something like this: ololo = 0 wololo = 0 trololo = 0
into something like this: ololo = 1 wololo = 2 trololo = 3 with geany regexp replacement? I tryed selecting column of zeroes and apply custom function: awk '$1=++a', but it didn't work really well: ololo = 1 2 3 wololo = trololo = so, is there a way to do this with regexp replace? -- View this message in context: http://geany-users.466218.n3.nabble.com/geany-regexp-replace-tp3379814p3379814.html Sent from the Geany-Users mailing list archive at Nabble.com. _______________________________________________ Geany mailing list [email protected] https://lists.uvena.de/cgi-bin/mailman/listinfo/geany
