Hmm, I'm pretty new to CSS selectors, but since I'm having to use the "id
ends with" selector syntax (e.g. $('[id$=endOfId]')), adding .visible (
$('[id$=endOfId].visible')) doesn't seem to work; I get an empty Navigator.
I guess I'll have to do the fallback, unless there's something I'm missing.
On Monday, August 24, 2020 at 10:11:49 AM UTC-5 micha.kutz wrote:
> The simplest solution would be to find a selector that is more precise as
> it would avoid creating unwanted Navigator objects. So if you can come up
> with something like
> $("#radio1*.visible*").click()
> It would be the best way.
>
> The fallback here would be to get a list of all Navigators and filter them
> using Groovy:
> $("#radio1").*find
> <https://docs.groovy-lang.org/latest/html/gapi/org/codehaus/groovy/runtime/DefaultGroovyMethods.html#find(Collection,%20groovy.lang.Closure)>*
> (it.*isDisplayed
> <https://gebish.org/manual/current/api/geb/navigator/Navigator.html#isDisplayed()>()*
> ).click()
>
> Am Mo., 24. Aug. 2020 um 16:54 Uhr schrieb Ben Frey <[email protected]>:
>
>> I have a page that has one visible instance of a radio button, but the
>> CSS selector (using id$=) returns more than one. How can I select only the
>> visible one so I can use click()?
>>
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