On Fri, 10 Aug 2012, Edward Kim wrote:

Hi All,

Instruction Sequence Number can be shown as follows.
    cprintf("[sn:%i] \n", instruction->seqNum);
The data type is %i. I'm unfamiliar with %i.

I'd like to compare an instruction SegNum with a specific sequence
number like this.
    if (instruction->SeqNum == 22162745)
Of course, this statement generates compile error.


And what's the error that's generated?

--
Nilay
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