Hi Shuchang,
In my opinion, your code are almost correct expect that the pkt->getSize() does return the cacheline size (64 in byte). You don’t need to multiply another 64 again. In fact, AbstractMemory has the function “access(PacketPtr pkt)” in which the data is also copied. You can read the code between line 352 and 372 in abstract_mem.cc to see how the data is copied. It does almost the same thing as you do. As a result, you can simply extend the AbstractMemory and use the access() to make sure the data is in pkt->getPtr<uint8_t>(); What you only need to do is to copy this data to your raw data pointer. -Tao From: [email protected] [mailto:[email protected]] On Behalf Of 单书畅 Sent: Sunday, January 27, 2013 6:31 AM To: [email protected] Subject: [gem5-users] question about reading out a whole DRAM row data Hi all, I am trying to modify the SimpleDRAM module to profile the data contents in phymem. In simple_dram.cc, the docodeAddr() function shows how to get the rank and the bank addresses for given request pkt. I wonder, given pkt->getAddr(), how to calculate the row address? It seems that, a dram row contains 64 (linesPerRow = 64) 64-Byte data blocks, and I want to read out the whole row data into a self-defined data structure ( namely row_data). The detailed codes are like this: uint8_t *myHostAddr = pmemAddr + (pkt->getAddr() - pkt->getAddr() % linesPerRow) - range.start; int row_size = pkt->getSize()*64; uint8_t row_data[row_size]; memcpy(row_data, myHostAddr , row_size ); // read the whole MEM row data out into the array structure: row_data I am not sure whether the calculation of the row address is right. Any advice will be appreciated. Regards, shuchang
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