How are you creating a.out? why this assembly code come into picture? On 22-Mar-2014 1:34 AM, "Zhongyuan Ni" <[email protected]> wrote:
> I want to modify the assembly code generated by gcc -S a.c. So u mean I > should also add this flag when generating the assembly code? > > Praxal Shah <[email protected]>于2014年3月21日星期五写道： > >> Compile your source code using static flag. >> Eg. gcc a.c -o a.out --static >> This will solve problem >> On 22-Mar-2014 1:27 AM, "Zhongyuan Ni" <[email protected]> wrote: >> >>> Hello, >>> >>> When we were trying to build the assembly test case Gem5 by using this >>> command: >>> >>> ./build/X86/gem5.fast configs/example/se.py -c a.out >>> >>> the following error popped up: >>> >>> fatal: Object file is a dynamic executable however only static >>> executables are supported! >>> >>> Any one knows why this happens? >>> >>> Thanks. >>> >>> _______________________________________________ >>> gem5-users mailing list >>> [email protected] >>> http://m5sim.org/cgi-bin/mailman/listinfo/gem5-users >>> >> > _______________________________________________ > gem5-users mailing list > [email protected] > http://m5sim.org/cgi-bin/mailman/listinfo/gem5-users >
_______________________________________________ gem5-users mailing list [email protected] http://m5sim.org/cgi-bin/mailman/listinfo/gem5-users
