In the example below, I would expect the statement $div//xh:a[1] to return the first <a> element, but instead, it returns two <a> elements. Curiously, if I filter for the second <a> element using [2], it works. What am I missing?
xquery version "1.0-ml"; declare namespace xh = "http://www.w3.org/1999/xhtml";; <lds-terms> { for $letter at $ctr in ("A") let $url := concat( "http://scriptures.lds.org/en/bd/";, lower-case( $letter ), "/contents" ) let $page := xdmp:tidy( xdmp:http-get( $url )[2] )//xh:d...@class = "contents"] return for $div in $page//xh:d...@class = "topics"] return <term>{ $div//xh:a[1] }</term> } </lds-terms> Stewart, This is because your expression: $div//xh:a[1] Means return the first xh:a element child of any descendent node under xh:d...@class = "topics"]. The fact that you get multiple nodes back means that there are multiple descendent elements of a given xh:d...@class = "topics"] that have an xh:a child. What you probably want to do instead is: ($div//xh:a)[1] Which means return the first node of the sequence $div//xh:a. Kelly _______________________________________________ General mailing list [email protected] http://xqzone.com/mailman/listinfo/general
