Hi David, To make sure I understood: you would like to order search results by the number of occurrences of the searched phrase? Or perhaps pick the one with the highest count or so? Scoring is related to relevance ranking. You need to read the search guide (http://developer.marklogic.com/pubs/) to understand how it is being calculated. I am certain it involves more than just the times a phrase occurs. Ordering results on occurrence counts will most likely have to be done with a tailor-made FLWOR...
Kind regards, Geert > drs. G.P.H. (Geert) Josten Consultant Daidalos BV Hoekeindsehof 1-4 2665 JZ Bleiswijk T +31 (0)10 850 1200 F +31 (0)10 850 1199 mailto:[email protected] http://www.daidalos.nl/ KvK 27164984 P Please consider the environment before printing this mail. De informatie - verzonden in of met dit e-mailbericht - is afkomstig van Daidalos BV en is uitsluitend bestemd voor de geadresseerde. Indien u dit bericht onbedoeld hebt ontvangen, verzoeken wij u het te verwijderen. Aan dit bericht kunnen geen rechten worden ontleend. > From: [email protected] > [mailto:[email protected]] On Behalf Of > Steiner, David J. (LNG-DAY) > Sent: donderdag 29 april 2010 18:33 > To: [email protected] > Subject: [MarkLogic Dev General] Search API: phrase and simple score > > I am trying to simply count whether a phrase exists in a > document or not, thus I think "simple-score" should work for me. > > > > If I do this: > > let $search := > > search:search('"new trial"', > > <options xmlns="http://marklogic.com/appservices/search";> > > <page-length>100</page-length> > > <search-option>score-simple</search-option> > > </options> > > ) > > > > I get a score of 8 for each doc that has at least 1 > occurrence of '"new trial"'. Note: I have "fast phrase > searches" set to true. > > > > If I do '"trial of [something]"', I get a score of 16 for > each document that has '"trial of [something]"'. And, if I > do '"new trial of [something1]"', I actually get 24... > > > > What's going on here? > > > > An esteemed colleague of mine explains that the "fast phrase" > index only allows for bi-grams and thus, a 3 word phrase will > always have a score of 2 (i.e., simple-score of 16) when that > phrase is matched because it is made up of 2 bi-grams. > > > > I'd like for a phrase, no matter how long, to be counted as > 1. How can I get the counting effect that I want? > > > > Do I always have to rely on the fact that the simple-score > for an exact match of a phrase will be 8 * (n - 1), where n > is the number of terms in a phrase? > > > > Is a partial match for a phrase ever returned? If my phrase > is "something1 something2 something3", I won't ever get a > score of 8, correct? I'll either get a match with a score of > 16, or nothing. > > > > So, if I have '"something1 something2 something3" OR word' my > possible results are ONLY: > > 24 - I matched the phrase and the word > > 16 - I matched the phrase > > 8 - I matched the word > > No other possibilities, right? > > > > Thanks, > > David Steiner > > Consulting Research Scientist > > Global Architecture & Research iLabs > LexisNexis Group > > [email protected] > <mailto:[email protected]> > > Toll Free: 800-227-9597 ext. 51894 > > Direct: 937-865-1894 > > > > _______________________________________________ General mailing list [email protected] http://xqzone.com/mailman/listinfo/general
