Add the diacritic characters to the regex bracket list with a-zA-z.
 On May 11, 2012 6:08 AM, "Rajasekaran, Santhosh" <
santhosh.rajaseka...@hmhpub.com> wrote:

> Hi Jakob,
>
> Thanks, Ya it worked well, but it also removes the diacritics character
> also.
> If i do not want to remove diacritics the what to do?
>
> Eg:  -->
> let $string := "Peña, replaces dia char"
> return replace($string, '[^a-zA-Z]+', '')
> ==> Peareplacesdiachar
>
> I need "Peñareplacesdiachar"
>
> Thanks
> Santhosh
>
>
>
> ________________________________________
> From: general-boun...@developer.marklogic.com [
> general-boun...@developer.marklogic.com] On Behalf Of Jakob Fix [
> jakob....@gmail.com]
> Sent: Thursday, May 10, 2012 10:22 AM
> To: MarkLogic Developer Discussion
> Subject: Re: [MarkLogic Dev General] Need to Remove spaces, punctuations,
> parens and ect., from the given string (need to remove all character other
> than A-Z and 0-9)
>
> Hi,
>
> it's probably easier if you declare the character groups you want to
> keep and excluding everything else, like so:
>
> let $string := "AB cd/EF;gh"
> return replace($string, '[^a-zA-Z]+', '') (: everything that's not an
> alphabetical character will be replaced :)
> ==> "ABcdEFgh"
>
> cheers,
> Jakob.
>
>
> On Thu, May 10, 2012 at 4:00 PM, Rajasekaran, Santhosh
> <santhosh.rajaseka...@hmhpub.com> wrote:
> > Hi Folks,
> >
> >
> >
> >                 I have the below requirement in Xquery.
> >
> >
> >
> > Given a string I need to remove spaces, punctuation, parens and etc.,
> > (I.e)except alpha(A-Z or a-z) and numeric 0-9
> >
> >
> >
> > Eg:
> >
> >
> >
> > Input                                       Expected Output
> >
> >
> >
> > San & co.,                              Sanco
> >
> > It is a string                            Itisastring
> >
> > New (value)                          Newvalue
> >
> > At,the hill +  school             Atthehillschool
> >
> > Oh!.. is it, I don’t know       OhisitIdontknow
> >
> >
> >
> > Please let me know how do I achieve this. Do I need to add all this
> > characters (spaces,punctuation,parens and etc., in regular expression and
> > replace that one by one) using fn:replace() function.
> >
> > Or
> >
> > Do we have any other better suggestion?
> >
> >
> >
> > Thanks & Regards,
> >
> > Santhosh
> >
> >
> > _______________________________________________
> > General mailing list
> > General@developer.marklogic.com
> > http://developer.marklogic.com/mailman/listinfo/general
> >
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