Hi, Karthik:
Basically, you need to construct a new version of the doc root element
that doesn't have the b child element but has all other child nodes. If
it is just a single exclusion, a simple predicate might be best:
xquery version "1.0-ml";
for $m in fn:doc()
return document {
<doc>{
$m/doc/node()[empty(self::b)]
}</doc>
}
If you need to exclude lots of stuff, you're probably better off with
typeswitch:
xquery version "1.0-ml";
for $m in fn:doc()
return document {
<doc>{
for $node in $m/doc/node()
return typeswitch($node)
case element(b) return ()
default return $node
}</doc>
}
Hoping that's useful,
Erik Hennum
________________________________________
From: [email protected]
[[email protected]] On Behalf Of
[email protected] [[email protected]]
Sent: Thursday, June 14, 2012 7:25 AM
To: [email protected]
Subject: [MarkLogic Dev General] How to exclude some elements from marklogic
xquery output?
Hi,
I want to exclude some elements from xquery output..
For ex: if I have many documents with the following xml ,
<doc>
<a>a</a>
<b>b</b>
</doc>
I want to return all the documents, but element <b> must be excluded in all
these documents.
for $m in fn:doc()
return $m
Above xquery will return all the documents as it is. Can someone please let me
know how to exclude only element <b> before returning the document. Is there
any xquery or marklogic function readily available to ignore some elements
while returning the response? I know that we can easily achieve this using
XSLT. But, is it possible using Xquery or marklogic function?
Thanks and Regards,
Karthik
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