It might. I guess you could always try and measure. Let us know what
happens if you do.
-Mike
On 06/22/2012 06:22 PM, Danny Sinang wrote:
Thanks. What if i do fn:reverse($pageSessionLogs) and then
subsequence($reversed,1) ? Would that be even better ?
Danny
On Jun 22, 2012, at 5:23 PM, Micah Dubinko
<[email protected] <mailto:[email protected]>> wrote:
An efficient way is to use fn:subsequence instead of a predicate. -m
On Jun 22, 2012, at 2:00 PM, Damon Feldman wrote:
Danny,
Try subsequence($pageSessionLogs, count($pageSessionLogs), 1)
Anything in square brackets is evaluated once for each element of
the sequence, so if you profile that you’ll see something like
“postion()=last()” evaluated many times – it just looks like an
array index due to a syntactic sugar.
Yours,
Damon
*From:* [email protected]
<mailto:[email protected]>
[mailto:[email protected]
<mailto:[email protected]>] *On Behalf Of
*Danny Sinang
*Sent:* Friday, June 22, 2012 4:24 PM
*To:* general
*Subject:* [MarkLogic Dev General] Faster alternative to fn:last()
Hello,
I'm trying to get the first and last documents in a sequence. The
code goes like this :
let $firstLog := $pageSessionLogs[1]
let $lastLog := $pageSessionLogs[fn:last()]
After doing some timings, it looks like the 2nd line always takes
around 30 milliseconds. And since I'm doing this in a loop, the
delays add up significantly.
Is there a faster way of getting the last sequence member ?
Regards,
Danny
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