As a follow-up, we found that the query was super fast with a small dataset
(e.g., 10,000 records). On the other hand, with a large dataset (40 million,
and pulling around 1 milllion records), we found that the query would be super
fast with 1 or 2 facets, e.g.:
let $tuples :=
cts:value-tuples(
(
cts:element-reference(xs:QName("Site"))
),
(),
cts:and-query((
cts:element-range-query(xs:QName("Audit_Date"), ">",
xs:date("2010-01-01")),
cts:element-range-query(xs:QName("Audit_Date"), "<", xs:date("2011-01-01"))
))
)
or
let $tuples :=
cts:value-tuples(
(
cts:element-reference(xs:QName("Site")),
cts:element-reference(xs:QName("Department"))
),
(),
cts:and-query((
cts:element-range-query(xs:QName("Audit_Date"), ">",
xs:date("2010-01-01")),
cts:element-range-query(xs:QName("Audit_Date"), "<", xs:date("2011-01-01"))
))
)
but would take a massive performance hit once the facets are increased to 3,
and 4 was much slower again. E.g.:
let $tuples :=
cts:value-tuples(
(
cts:element-reference(xs:QName("Site")),
cts:element-reference(xs:QName("Department")),
cts:element-reference(xs:QName("LOB"))
),
(),
cts:and-query((
cts:element-range-query(xs:QName("Audit_Date"), ">",
xs:date("2010-01-01")),
cts:element-range-query(xs:QName("Audit_Date"), "<", xs:date("2011-01-01"))
))
)
By performance hit, I mean the first two queries would take 1 second each.
Pulling 3 facets would take 250 seconds, and pulling 4 facets would take 350
seconds. Anyone have any idea of what is going on under the hood to lead to
such a breaking point between 1-2 facets and more facets? Any better way to do
the query in such circumstances to avoid the performance hit?
Thanks.
________________________________
From: general-boun...@developer.marklogic.com
<general-boun...@developer.marklogic.com> on behalf of Mark Shanks
<markshanks...@hotmail.com>
Sent: Wednesday, 21 September 2016 4:35:32 AM
To: MarkLogic Developer Discussion
Subject: Re: [MarkLogic Dev General] Speeding up xquery returning aggregates
Hi Rob,
Your suggestion worked very well! Super fast, at least with the relatively
small dataset I'm using at present.
Thanks.
________________________________
From: general-boun...@developer.marklogic.com
<general-boun...@developer.marklogic.com> on behalf of Rob Szkutak
<rob.szku...@marklogic.com>
Sent: Saturday, 17 September 2016 7:28:01 AM
To: MarkLogic Developer Discussion
Subject: Re: [MarkLogic Dev General] Speeding up xquery returning aggregates
Hi,
The fastest way to do that I can think of would be to index Data/Site,
Data/Department, Data/LOB, /Data/Audit_Date.
Next, you could use cts:value-tuples() to build your result set directly out of
the in-memory indexes without needing to pull document fragments . Finally, you
would just need to return your concatenation.
It would look something like this (Not tested) :
let $tuples :=
cts:value-tuples(
(
cts:element-reference(xs:QName("Site")),
cts:element-reference(xs:QName("Department")),
cts:element-reference(xs:QName("LOB"))
),
(),
cts:and-query((
cts:element-range-query(xs:QName("Audit_Date"), ">",
xs:date("2010-01-01")),
cts:element-range-query(xs:QName("Audit_Date"), "<",
xs:date("2011-01-01")),
cts:or-query((
cts:element-value-query(xs:QName("Classification"), "Finding"),
cts:element-value-query(xs:QName("Classification"), "Observation")
))
))
)
for $each in $tuples
return
fn:concat($each[1], |, $each[2], |, $each[3], cts:frequency($each))
Best,
Rob
Rob Szkutak
Senior Consultant
MarkLogic Corporation
rob.szku...@marklogic.com
www.marklogic.com<http://www.marklogic.com>
________________________________
From: general-boun...@developer.marklogic.com
[general-boun...@developer.marklogic.com] on behalf of Mark Shanks
[markshanks...@hotmail.com]
Sent: Friday, September 16, 2016 3:55 PM
To: 'General MarkLogic Developer Discussion'
Subject: [MarkLogic Dev General] Speeding up xquery returning aggregates
Hi,
I'm trying to find the best way to return the results of what would be the
following equivalent sql statement:
select count(*) from Data
where Audit_Date > "2010-01-01" and Audit_Date < "2011-01-01" and
(Classification = "Finding" or Classification = "Observation")
group by Site, Department, LOB
I didn't test this sql statement, but it should give you the idea... Anyway, I
came up with the following xquery equivalent:
for $s in distinct-values(/Data/Site)
return
for $d in distinct-values(/Data/Department)
return
for $lob in distinct-values(/Data/LOB)
return concat($s,'|',$d,'|',$lob,'|',
count(
for $x in (/Data[Site=$s and Department=$d and LOB=$lob and
(Classification='Finding' or Classification='Observation')])
let $date as xs:dateTime := $x/Audit_Date
where $date gt xs:dateTime("2010-01-01T00:00:00")
and $date lt xs:dateTime("2011-01-01T00:00:00")
return ($x)
)
)
It works fine and is not super-slow, but isn't particularly fast either. Is
this the most efficient way to get this type of information out of marklogic?
Assuming the fields are indexed, would some search command be faster? Or maybe
subset the data better?
Thanks,
Mark
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