fR is not a function in your example. You can make it a function like so: fR=:3 : '?10' ((fR , ])^: 3)'' 5 3 9 ((fR , ])^: 3)'' 8 3 1
On Sat, Dec 15, 2012 at 4:34 AM, Dr. Heinz Schild < [email protected]> wrote: > A Power Conjunction normally evaluates a function, here rF, only on the > first call. Is there a way to compute the value of such a function on each > call? > An example: > fR =: ?10 > ((fR , ])^: 3)'' > 6 6 6 > Regards > Heinz > ---------------------------------------------------------------------- > For information about J forums see http://www.jsoftware.com/forums.htm > ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
