The last sentence in the page you mentioned should already had said something about the ranks. Did you miss it?
Вс, 03 янв 2016, Matthew Baulch написал(а): > (0, 1) Thanks for your kind words. It does seem a very supportive and > knowledgeable community. > > (3) This makes sense now. Thanks too for pointing me to NuVoc. It seems an > improvement in some respects, though it appears not to be distributed with > J. > > (4) I particularly enjoy the terseness of the original Voc., and its > availability offline. Perhaps a static copy of NuVoc could be distributed > with J, and the original Voc. could include a warning about its > obsolescence? > > I'd love to see J thrive in the future. It seems the case with all > software, whether programming language or not, that documentation very > important. J's is very good. This is the only shortcoming I can see. > > Matt > On 3 Jan 2016 1:11 pm, "Henry Rich" <[email protected]> wrote: > > > 0. Welcome to J! > > > > 1. If you are able to get that far entirely on your own, my hat is off to > > you. You're a J natural, and I think you'll enjoy the language. > > > > 2. Your analysis is brilliant, though not quite perfect. rv must mean, > > not the right rank of v, but instead the rank of a result-cell of v. And > > even then, the equivalence would not be exact, because of changes to > > result-cells when they are assembled into the overall result of v. > > > > 3. The best resource for learning J is NuVoc. It fills in the gaps in > > the Dictionary, corrects errors like this one, and has tutorial > > information. For u@v, see > > > > http://code.jsoftware.com/wiki/Vocabulary/at > > > > 4. The Dictionary is not actively maintained. Don't expect an update. > > But NuVoc is a Wiki, so do what you can to improve it! > > > > Henry Rich > > > > > > > > On 1/2/2016 8:59 PM, Matthew Baulch wrote: > > > >> The equivalence (from the voc. page for @) > >> > >> x u@v y ↔ u x v y > >> > >> only seems to apply in some cases. For instance, with > >> > >> x =: 1 2 3 4 > >> y =: 5 6 7 8 > >> u =: */ > >> v =: + > >> > >> this is most certainly false. After exploring a number of cases, > >> it seems likely that > >> > >> x u@v y ↔ u"rv x v y > >> > >> where rv is the right rank of v. Is this true in all cases? > >> If so, I'd be grateful if the dictionary could be updated accordingly. > >> > >> Matt Baulch > >> ---------------------------------------------------------------------- > >> For information about J forums see http://www.jsoftware.com/forums.htm > >> > > > > ---------------------------------------------------------------------- > > For information about J forums see http://www.jsoftware.com/forums.htm > ---------------------------------------------------------------------- > For information about J forums see http://www.jsoftware.com/forums.htm -- regards, ==================================================== GPG key 1024D/4434BAB3 2008-08-24 gpg --keyserver subkeys.pgp.net --recv-keys 4434BAB3 gpg --keyserver subkeys.pgp.net --armor --export 4434BAB3 ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
