Henry Rich wrote: > Or > > 1+1x1^0j1p1 > 0 > What's wrong with
1+^0j1p1 0 or to bring out the fact that the exponent is imaginary 1+^j.1p1 0 1+^j.o.1 0 Best wishes, John ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
