Dan Bron wrote: > operation to reveal the difference, because no difference exists. > So, despite my little "proof": > > (^._1) -: 0 j.-1p1 > 0
_1 -: ^ 0 j.-1p1 1 (^._1) -: (^.^ 0 j.-1p1) 1 > I'm not a mathematician, but it seems to me that the right solution > is to express ^._1 as 0 j. (+,-) 1p1 . But no one does. That approach gets into infinitely fat results in many common cases. This, all too easily, can lead to a variety of obscure errors. Simple is good. -- Raul ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
