Thing I learned today:
3 : '...' " 1
doesn't need parentheses.
A good way to learn that
foo =: 3 : 0
yada yada yada
) " 1
doesn't work is to try it. For example, I just tried:
3 : 0 ] 2
y. + 10 NB. Yes, I'm attached to y.
)
12
and I learned something else.
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|\/| Randy A MacDonald | APL: If you can say it, it's done.. (ram)
|/\| [EMAIL PROTECTED] |
|\ | |If you cannot describe what you are doing
BSc(Math) UNBF'83 |as a process, you don't know what you're doing.
Sapere Aude | - W. E. Deming
Natural Born APL'er | Demo website: http://156.34.82.146/
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----- Original Message -----
From: "Fred Bone" <[EMAIL PROTECTED]>
To: "General forum" <[email protected]>
Sent: Tuesday, August 15, 2006 6:09 AM
Subject: Re: [Jgeneral] RE: [Jbeta] Possible link error in Dictionary
On 14 Aug 2006 at 12:10, Roger Hui said:
Do you understand the following?
sum =: +/
sum1=: +/"1
sum1 is defined to apply to the rank 1 cells of
the argument. Now:
foo=: 3 : 0
blah blah blah
)
foo1=: 3 : 0 " 1
blah blah blah
)
The pattern regarding rank is the same between
sum/sum1 and foo/foo1 . What is different is
that for (m : 0) , the lines of the object being
defined are taken from the following lines,
terminated by a ) on a line by itself. It may be
helpful to compare the above to the following:
sum=: +/
sumEach=: +/&.>
foo=: 3 : 0
blah blah blah
)
fooEach=: 3 : 0 &.>
blah blah blah
)
OK, but given
foo2 =. 3 : 'blah blah blah' "1 0
how is the novice to know that the construct with the : 0 form is not
foo =: 3 : 0
blah blah blah
) "1 0
?
"Terminated by ) on a line by itself" is a major clue, of course, but
ISTM that an example somewhere obvious would be useful.
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