>  Thus x u/ y is equivalent to 
>  x  u"(lu,_) y where lu is the left rank of u .

   (i.3) <@(+"0 _) i.3
+-----+-----+-----+
|0 1 2|1 2 3|2 3 4|
+-----+-----+-----+
   (i.3) <@(+/) i.3
+-----+
|0 1 2|
|1 2 3|
|2 3 4|
+-----+

That does not look equivalent.

What it should say: x u/ y is equivalent to x u"(lu,_)"_ y

   (i.3) <@(+"0 _"_) i.3
+-----+
|0 1 2|
|1 2 3|
|2 3 4|
+-----+


--- Roger Hui <[EMAIL PROTECTED]> wrote:

> You should also read section II b of the dictionary:
> 
> http://www.jsoftware.com/help/dictionary/dictb.htm
> 
> and the immediately following sentence in the 
> dictionary entry for / :
> 
>  In general, each cell of x is applied to the 
>  entire of y .  Thus x u/ y is equivalent to 
>  x  u"(lu,_) y where lu is the left rank of u .
> 
> 
> 
> ----- Original Message -----
> From: June Kim <[EMAIL PROTECTED]>
> Date: Friday, September 22, 2006 10:42 am
> Subject: Re: Cell (was Re: [Jgeneral] I expect a table of ordered pairs for 
> this)
> 
> > 2006/9/23, Roger Hui <[EMAIL PROTECTED]>:
> > > >   the rank of the verb determins the cells.
> > >
> > > This is not correct.  For example, it make sense
> > > to talk about the 1-cells of a matrix (the rows
> > > of a matrix) without reference to any verb.
> > >
> > 
> > >From your explanation and the dictionary, I suppose that the 
> > followingsentence alone:
> > 
> > > u/ applies u between each cell of x and the entire y.
> > 
> > does not imply anything about the rank of applying u. This was my
> > initial confusion when reading it. From the context it read like using
> > "cell" implied the (left) rank of u.


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