Don Guinn wrote:
For 6 u: it says that pairs of characters are converted to wchar. On Windows/Intel where the low-order byte of a 16 bit integer comes first: a.i.6 u:'A',0{a. 65Would the above expression still be the same on processors where the high-order byte comes first? It seems to me that it should. I shouldn't have to test the type of processor I'm using to determine how 6 u: works.
Roger's response http://www.jsoftware.com/pipermail/general/2004-July/017866.html -- regards, bill ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
