-: is lenient when comparing emties. eg,
($0)-:(0$<'anything')
1
10{.$0
0 0 0 0 0 0 0 0 0 0
10{.(0$<'anything')
+++++++++++
|||||||||||
+++++++++++
Murray Eisenberg wrote:
But:
($0)-:(0$0)
1
Mark D. Niemiec wrote:
"Henry Rich" <[EMAIL PROTECTED]> wrote:
$0 is the shape of a scalar: an empty numeric list.
So it is the same as 0$0 .
In DoJ: The ace (a unit, from Latin as) is denoted by a: . It is the
boxed empty list <$0 .
Is it a typo? Look like should be <0$0 instead.
Actually, they are equal, but not identical.
0$0 is boolean, but $0 is integer:
t =: 3!:0
t 0
1
t 0$0
1
t $0
4
t >a:
1
-- Mark D. Niemiec <[EMAIL PROTECTED]>
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--
regards,
bill
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