Is this behaviour in the ISO Standard APL?
----- Original Message ----- From: [EMAIL PROTECTED] Date: Friday, March 16, 2007 12:48 pm Subject: Re: [Jgeneral] definition of a: > In modern APLs you can not []EX'[]IO' and localizing []IO has no > effect on > the execution of FOO. > Basically, the global []IO takes over if the localized one is > undefined > and []<-[]EX'IO' gives 0. > Roger Hui <[EMAIL PROTECTED]> > Sent by: [EMAIL PROTECTED] > 03/16/2007 02:41 PM > Please respond to > General forum <[email protected]> > > > To > General forum <[email protected]> > cc > > Subject > Re: [Jgeneral] definition of a: > > > > > > > Or: > > {quad}ex '{quad}io' > {iota}0 > > > > ----- Original Message ----- > From: Roger Hui <[EMAIL PROTECTED]> > Date: Friday, March 16, 2007 12:31 pm > Subject: Re: [Jgeneral] definition of a: > > > Execute foo in your APL where > > > > {del} z {is} foo ; {quadio} > > z {is} {iota} 0 > > {del} > > > > > > > > ----- Original Message ----- > > From: ramacd <[EMAIL PROTECTED]> > > Date: Friday, March 16, 2007 12:19 pm > > Subject: Re: [Jgeneral] definition of a: > > > > > Hi Roger; > > > > > > Ok, I'm stumped: how does {iota}0 depend on {quad}io? > > > > > > >: ... > ------------------------------------------------------------------- > --- > For information about J forums see http://www.jsoftware.com/forums.htm > > ------------------------------------------------------------------- > --- > For information about J forums see http://www.jsoftware.com/forums.htm > ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
