Terrence
I think if you check the huge result sets occur when there are no
brackets around the first i.4
i.4 +/(i.4)
would be parsed as
i. (4 +/(i.4)
where 4 +/(i.4 )is the dyadic table adverb applied to addition. i.
applied to this generates the large set. i.e. integer list of shape
(4+/(i.4)
Cheers, bob
ps. as another noob, I look forward to correction if I haven't gotten
this quite right.
at least that is how it works for me.
On 28-Mar-07, at 11:26 AM, Terrence Brannon wrote:
Both (i.4) +/ (i.4) and i.4 +/ (i.4) parse the same, however
(i.4) +/ i.4 yields a huge result set.
How is it being parsed?
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