No, it exhibits no such inconsistent behavior. It appends zero items exactly where it should (as far as we can tell): [insert "empty array" joke of your choice here].
$(i.3),i.2 NB. 3 elements appended to 2 elements gives you 5 elements 5 $(i.3),i.1 NB. 3 elements appended to 1 element gives you 4 elements 4 $(i.3),i.0 NB. 3 elements appended to 0 elements gives you 3 elements 3 (i.3) -: (i.3),i.0 NB. something is equivalent to the same thing appended to nothing 1 OK, this is functionally the same as "discarding" items - in fact the common use of compression by a boolean is to remove the items corresponding to the falsity of some condition, e.g. (] #~ 0 ~: 3 | ]) i. 10 NB. Remove multiples of 3 1 2 4 5 7 8 On 4/18/07, Terrence Brannon <[EMAIL PROTECTED]> wrote:
On 4/18/07, Devon McCormick <[EMAIL PROTECTED]> wrote: > Each pair returns a value: > '0#n' returns a 0-length value; > '1#n' returns a 1-length value. > >From this, what would you suppose is the length of > '2#n'? the length would be 2 but what does J do with the 0-length values? toss'em like my append example? ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
-- Devon McCormick, CFA ^me^ at acm. org is my preferred e-mail ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
