load'trace' paren'_5 + _4' (_5 + _4) paren'-5 + -4' (- (5 + (- 4)))
Why? See the Dictionary's appendix E. Parsing and Execution > On Behalf Of Jose Mario Quintana > > (_5 + _4) = (-5) + (-4) > 1 > > (-5 + -4) = -(5 + -4) > 1 > > > > >> [mailto:[EMAIL PROTECTED] On Behalf Of > > [EMAIL PROTECTED] > > > > If I input: > > > > -5 + -4 > > > > I get: > > > > _1 > > > > But when I input: > > > > a=. -5 > > b=. -4 > > a + b > > > > I get: > > > > _9 > > > > Any comments for a newbie - ( did APL about 30 years ago for > > 6 months ) > > > > thanks > > ---------------------------------------------------------------------- > > For information about J forums see > > http://www.jsoftware.com/forums.htm > > ---------------------------------------------------------------------- > For information about J forums see http://www.jsoftware.com/forums.htm ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
