On 6/23/07, Mark D. Niemiec <[EMAIL PROTECTED]> wrote:
When I first saw this behaviour, I thought it was a bug. However, after thinking about it a while, it does make a kind of sense. After all, the sentence f"(-r) a behaves like f"(-r)"_ a
With this reasoning, + b. should return _ _ _ because +"0 is equivalent to +"0"_
It can't know the actual rank to apply to f without actually first seeing the ENTIRETY of its parameter(s), in order to determine the virtual rank
What is "it"? Anyways, with b. returning _ _ _ you cannot determine the actual rank to apply to f, even when you know all the parameters. (Well, unless I investigate f's definition, but that seems complicated.) -- Raul ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
