Raul observed:

>    ?.]3#100
> 46 55 79
>    ?."0]3#100
> 46 46 46


Roger, what is the rationale for not changing the advertised rank of  ?.  in 
the dictionary (and  b.  )?  Why not just give the
ranks of   ?.  as  _ _ _  ?  (I can understand why you wouldn't want to change 
the implementation to conform to the Dictionary's
spec of  0 0 0  ).

-Dan

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