Is # $ $. 67 a typo? Should it be # $ }. 67 (which is 1)?
metaperl.j wrote:
}. 67
# }. 67
0
$ }. 67
0
# $ $. 67
0
}. drops the leading item of its argument.
But in this case, I am wondering what exactly is returned when beheading an
atom.
I know the items of an atom is that atom. But what is left when it is
dropped? A rank-0 array with shape 0?
--
------------------------------------------------------------------------
|\/| Randy A MacDonald | APL: If you can say it, it's done.. (ram)
|/\| ramacd <at> nbnet.nb.ca |
|\ | | The only real problem with APL is that
BSc(Math) UNBF'83 | it is "still ahead of its time."
Sapere Aude | - Morten Kromberg
Natural Born APL'er |
-----------------------------------------------------(INTP)----{ gnat }-
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