> OpenSM will always use min-hop paths (no matter what routing algorithm > except maybe for LASH). > If you use the default algorithms OpenSM will tend to spread traffic > such that if you have used LMC=1 (2 LIDs per port) > The two paths going to LID0 and LID1 will go through different systems > or if not possible through different nodes. >
Using the same example you have mentioned, what happens if LMC=1and there are 2 paths (say P1, P2 and P2 is costlier than P1) between two nodes (say N1, N2). Will the openSM still configure two different paths for LID0 and LID1? -Mahesh > EZ _______________________________________________ general mailing list [email protected] http://lists.openfabrics.org/cgi-bin/mailman/listinfo/general To unsubscribe, please visit http://openib.org/mailman/listinfo/openib-general
