If you open up the religion timeline in firefox and select View-->page
source, and scroll down to the part near the bottom where it says:
tl = Timeline.create(document.getElementById("tl"),
bandInfos, Timeline.HORIZONTAL);
tl.loadXML("jewish.xml", function(xml, url) {
eventSourceJewish.loadXML(xml, url);
document.getElementById("jewish-event-count").innerHTML =
eventSourceJewish.getCount();
});
tl.loadXML("christianity.xml", function(xml, url) {
eventSourceChristianity.loadXML(xml, url);
document.getElementById("christianity-event-count").innerHTML =
eventSourceChristianity.getCount();
});
You will see the name of the two source xml files jewish.xml and
christianity.xml.
This tells you that they are at the same level as the page that displays
them so if you go to the address
http://simile.mit.edu/timeline/examples/religions/religions.html
and replace religions.html with jewish.xml you can view the data file for
the jewish timeline.
ditto for the christianity timeline.
Is this what you need?
HTH.
On 1/21/08, Omnigut The Merciless <[EMAIL PROTECTED]> wrote:
>
> Hi,
> for research reasons (and I'd gladly donate my info afterwards if you'd
> like it) I am trying to make a timeline of all religions, cults, and
> myths, including several different aspects of each, color coded, linked,
> searchable etc etc. However, I was wondering if you might have the data
> file for the religion timeline you already have on it (the Christianity
> and Judaism timeline), because I would like to see how to seperate three
> seperate timelines into one display. I'm sorry if this doesn't make
> sense, but I have no computer knowledge, and would like to do a "cut and
> paste" job with your data, replacing your events with my own. The data
> file I found was the jfk file, and that's just one timeline. With the
> Christianity/judaism you have two on the same page, and I'd like three
> (religion, myth, cult)
>
> I'm really very sorry for the bumbling of the above paragraph, but as I
> said, I have no computer knowledge apart from the very basics.
>
> Thank you for your time,
>
> Nick Broad
>
>
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