> i run "cvs update > /dev/null" or "cvs update | sed -e 's/<expression>/yyy/'"
> it still prints the same thing it always does. how do i capture this
> information?
cvs prints many of its messages to standard error (STDERR) instead of
standard output. In bourne-like shells (including bash), you use 2>
instead of > to redirect stderr (in csh-like shells it's different). See
the bash (or csh) man page for more information. Additionally, Google
found these pages with some information and examples:
http://tomecat.com/jeffy/tttt/shredir.html
http://www.losurs.org/docs/redirection
In your example, if you wanted to pass both stdout and stderr (this is,
everything cvs prints out) to a command, you could simply do:
cvs update 2>&1 | sed -e 's/<expression>/yyy/'
If you wanted to pass only stderr, it gets more complicated:
(cvs update > /dev/null) 2>&1 | sed -e 's/<expression>/yyy/'
Again: these examples work only in Bourne shell and its derivatives.
--Diego
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