Maxim Vexler wrote: >I can't quite understand the purpose of this "(alias; declare -f)" expression. > >
If you don't have any aliases or functions defined in your shell, you
won't see anything from running 'alias; declare -f'.
An example:
~ > alias e='echo'
~ > e foo
foo
~ > f() {
> echo "function"
> }
~ > f
function
~ > alias ; declare -f
alias e='echo'
f ()
{
echo "function"
}
-Richard
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