I'm trying to figure out how to do this sequence in this bash script.
The problem I'm having is how to make $i to change according to the
changes in $x
My current solution is a bit of a hack and stupid.
One more thing, my current solution will parse the file _each_ time for
_each_value/head which essentially means it reads the file multiple
times. Is there a better way so to reduce the # of reads/parses? (Does
awk parse the file once or multiple times, that is if I were to rewrite
the below entirely in awk language)
Thanks
#!/bin/bash
filename=$1
heads=6
tpi=7
x=0
y=1
z=1
clear
while (( $x < $heads ))
do
finaltpi=`cat $1 | awk "/TPI chosen/" | awk -v pat="$x" '{if
(NR==pat+1) print $5}'`
while (( $y <= $tpi ))
do
if [ "$x" -eq 0 ]
then
for i in `seq 1 7` <-----
do
tpiert=`egrep -i "(average)" $1 | awk -v pat="$i"
'{ if(NR==pat) print $5","$10}'`
echo $filename,$x,$y,$finaltpi,$tpiert
((y++))
done
elif [ "$x" -eq 1 ]
then
for i in `seq 8 14` <-----
do
tpiert=`egrep -i "(average)" $1| awk -v pat="$i"
'{ if(NR==pat) print $5","$10}'`
echo $filename,$x,$y,$finaltpi,$tpiert
((y++))
done
elif [ "$x" -eq 2 ]
then
for i in `seq 15 21` <-----
do
tpiert=`egrep -i "(average)" $1 | awk -v pat="$i"
'{ if(NR==pat) print $5","$10}'`
echo $filename,$x,$y,$finaltpi,$tpiert
((y++))
done
elif [ "$x" -eq 3 ]
then
for i in `seq 22 28` <-----
do
tpiert=`egrep -i "(average)" $1 | awk -v pat="$i"
'{ if(NR==pat) print $5","$10}'`
echo $filename,$x,$y,$finaltpi,$tpiert
((y++))
done
elif [ "$x" -eq 4 ]
then
for i in `seq 29 35` <-----
do
tpiert=`egrep -i "(average)" $1 | awk -v pat="$i"
'{ if(NR==pat) print $5","$10}'`
echo $filename,$x,$y,$finaltpi,$tpiert
((y++))
done
elif [ "$x" -eq 5 ]
then
for i in `seq 36 42` <-----
do
tpiert=`egrep -i "(average)" $1 | awk -v pat="$i"
'{ if(NR==pat) print $5","$10}'`
echo $filename,$x,$y,$finaltpi,$tpiert
((y++))
done
fi
done
let "y=1"
((x++))
done
--
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