Ah right, I didn't think about it but "-" is a special character inside of
character classes in Java regular expressions. So "|-|" is parsed as a
range from | to | (inclusive.) I guess when the - is the first character
in the class the parser assumes it should be treated as an escape, but if
you want to be explicit you can also escape it with a \. Backslashes also
must be escaped in Java string literals so the end result would be
.split("[+\\-Z]")
--
David Winslow
OpenGeo - http://opengeo.org/
On Tue, Jul 17, 2012 at 3:28 AM, Mauricio Pazos <[email protected]>wrote:
> On Monday, July 16, 2012 09:47:59 AM David Winslow wrote:
> > Actually, the square brackets denote a character class, so logical OR is
> > the default behavior and | has no special meaning.
> String.split("[-|+|Z]")
> > will split on any of the characters '-' '+' '|' and 'Z' (note that the
> pipe
> > character is included in this list! that's probably not intended.) See
> > http://docs.oracle.com/javase/6/docs/api/java/util/regex/Pattern.html#cc
> Thanks for clarification. The, bug here is related with the sequence in the
> character list. It looks like is not equal
> str = "aaaa-bbbb"
> str.split("[-|+|Z]") Not equal to str.split("[+|-|Z]")
>
> but
>
> str = "aaaa-bbbb"
> str.split("[-+Z]") equal to str.split("[+-Z]")
>
> cheers
> --
> Mauricio Pazos
>
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