Dear Justin,
thanks, that's exactly what I needed - I know that the JTS geometry will
be in whatever the native units are , that's fine with me.
Would it be possible to update the javadoc to say tha the Object is
actually the geometry? I was suspecting that, but was not sure whether
it is the original feature or the geometry.
Is there any equivalent method to get back to the generating feature (so
that one could get some of the other attributes, maybe containing other
values for weights?)
Thanks
Martin
On 9/1/2010 5:20 PM, Justin Deoliveira wrote:
Hi Martin,
Yeah you should be able to get at the underlying LineString by calling
e.getObject(). Something like:
DijkstraIterator.EdgeWeigter weighter =new
DijkstraIterator.EdgeWeighter() {
public double getWeight(Edge e) {
LineString l = (LineString) e.getObject();
return l.getLength();
}
}
However the linestring has no notion of units. That will depend on
whatever coordinate system your data is in.
On Wed, Sep 1, 2010 at 10:55 AM, Martin Tomko <[email protected]
<mailto:[email protected]>> wrote:
Dear All,
I am using the Graph api to construct a graph based on lineStrings -
that works perfectly. I would like to do a shortest path computation
based on geographical distance, and need to implement a Weighter.
the docs show this snippet:
DijkstraIterator.EdgeWeigter weighter =new
DijkstraIterator.EdgeWeighter() {
public double getWeight(Edge e) {
return 1.0;//constant
}
}
which results in a constant weight for an edge of 1.
How do I get the actual length of an edge, in the original
feature's units...
I need the values also for other purposes, so really neend to
access the edge length property.
Is it possible?
Thanks
Martin
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Justin Deoliveira
OpenGeo - http://opengeo.org
Enterprise support for open source geospatial.
--
Martin Tomko
Postdoctoral Research Assistant
Geographic Information Systems Division
Department of Geography
University of Zurich - Irchel
Winterthurerstr. 190
CH-8057 Zurich, Switzerland
email: [email protected]
site: http://www.geo.uzh.ch/~mtomko
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