This should give you the fractional part of a double:
num = 123.456
num = (ceil(num) - 1) - num
As for mod, maybe you could use something like this? (I've not tested
this)
if num mod 1 then
//fraction
else
//integer
end if
hth,
Erick
On Jan 20, 2006, at 1:31 AM, Barrie Jones wrote:
The problem is that str(number) returns scientific notation for
numbers greater than 6 digits. This means that I must test the
number without using the str function. The example below (Num1 mod
Num2) only works for integers. Since my numbers can be integer or
decimal, I don't think the Mod operator can be used to test for a
fractional part. Is there a function that returns only the
fractional part of a number?
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