Joseph J. Strout wrote:
At 4:23 PM -0700 4/6/06, Charles Ross wrote:
From what you say, I would think that the problem is that Val()
returns a Double, which means that Val("1") returns 1.0, not 1, and
1.0 isn't a valid key in the Dictionary, so I get the error about the
nonexistent key.
Yep, that sounds about right to me. If this is something you'll need
to do a lot, you might want to add your own IntVal function, that
takes a string and converts it to an integer.
Best,
- Joe
Why not just use the 'numeric' string as the key and bypass the
conversion step?
Ken
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