On Jan 18, 2007, at 10:28 AM, Phil Heycock wrote:
How about RegEx? (I didn't test the following, but something like
it ought
to work).
Dim reg As New RegEx
Dim regResults As RegMatch
reg.SearchPattern = "\b(\d+)\b" // word boundary - word - word
boundary
regResults = reg.Search(yourText)
Dim matchNum As Integer
For matchNum = 1 To regResults.SubExpressionCount
nextWord = regResults.SubExpressionString(matchNum)
Next matchNum
I'm teaching myself RegEx and developed something akin to this
methodology you suggested.
However, what I'm experiencing is 'odd'.
I've got a source text that has the word "test" in it several times.
But for some strange reason the regResults.SubExpressionCount is only
returning a value of 1. Not the number of instances of the word
"test" in the target string.
Here's my code....
// method to test aspects of Regular Expressions
dim rg as New RegEx
dim theMatch as RegExMatch
dim strInput as string
dim strQuots as string
dim srchPatt as string
dim iCount as integer
dim i as integer
strInput = "test this 'chuck pelto' test 'susan pelto' test another"
srchPatt = "test" // look for word "test"
rg.SearchPattern = srchPatt
theMatch = rg.Search(strInput)
iCount = theMatch.SubExpressionCount
for i = 1 to iCount
strQuots = theMatch.SubExpressionString(i)
next
Why is it only returning a value of 1 when there are three instances
of the word "test" in the target string?
Regards,
Chuck
_______________________________________________
Unsubscribe or switch delivery mode:
<http://www.realsoftware.com/support/listmanager/>
Search the archives of this list here:
<http://support.realsoftware.com/listarchives/lists.html>